Person joining or leaving in between
Duration: 12 min
This video lesson is available to enrolled students.
AI Summary
An AI-generated summary of this video lecture.
This educational video is a lecture on solving time and work problems, a common topic in competitive exams. The instructor, Yash Jain Sir, presents a series of four problems, each with a different scenario involving multiple workers. The core concept taught is that the total work done is the sum of the work done by each individual, which is calculated as (Time Worked / Time to Complete Alone). The video demonstrates a systematic approach: first, defining variables for the time each person takes to complete the work alone, then setting up an equation where the sum of the fractions of work completed by each person equals 1 (the whole work). The first problem involves two people working together for a period before one leaves. The second problem features three people with staggered start and end times. The third problem uses the combined work rates of pairs to find an individual's rate. The fourth problem uses the LCM method to simplify calculations. The instructor uses a digital whiteboard to write out the equations and solve them step-by-step, providing a clear, methodical guide for students.
Chapters
0:00 – 2:00 00:00-02:00
The video opens with a title card featuring the text 'TIME & WORK' and an illustration of a person working at a computer. It then transitions to a lecture slide for Question 1. The problem states that Gangadhar and Shaktimaan can complete a work in 18 and 24 days respectively. They work together for 8 days, after which Gangadhar leaves, and Shaktimaan finishes the remaining work. The question asks for the number of days Shaktimaan took to finish the remaining work. The instructor, Yash Jain Sir, is visible in a small window in the bottom right corner. The slide also shows the answer as '16/3 days' and the source as 'COGNIZANT 2018'. The instructor begins to explain the problem, setting up the scenario and introducing the concept of work rates.
2:00 – 5:00 02:00-05:00
The instructor explains the general formula for time and work problems. He writes on the digital board: 'Time Worked by A / A's alone time + Time Worked by B / B's alone time = 1'. He then applies this to the first problem, defining 'A' as Gangadhar (18 days) and 'B' as Shaktimaan (24 days). He writes the equation: '8/18 + x/24 = 1', where 'x' is the number of days Shaktimaan worked alone. He proceeds to solve the equation step-by-step, first simplifying 8/18 to 4/9, then finding a common denominator of 72, and finally solving for 'x' to get 16/3 days. The instructor emphasizes that the sum of the work done by each person must equal the total work, which is 1.
5:00 – 10:00 05:00-10:00
The video transitions to Question 2. The problem states that Ajay, Vijay, and Sujoy can complete a work in 10, 12, and 15 days respectively. They all start together, Ajay leaves after 2 days, and Vijay leaves 3 days before the work is completed. The question asks for the total time taken to complete the work. The instructor sets up the equation: '2/10 + (x-3)/12 + x/15 = 1', where 'x' is the total time. He explains that Ajay worked for 2 days, Vijay worked for (x-3) days, and Sujoy worked for the full 'x' days. He then solves the equation by finding a common denominator of 60, simplifying to '12 + 5(x-3) + 4x = 60', and solving for 'x' to get 7 days. The instructor then moves to Question 3, which states that A and B together can do a work in 12 days, and B and C together can do it in 16 days. After A works for 5 days, B for 7 days, and C for 13 days, the work is completed. The question asks for the number of days C alone would take to finish the work. The instructor sets up the equation: '5/12 + 7/16 + 13/x = 1'.
10:00 – 11:47 10:00-11:47
The instructor continues solving Question 3. He simplifies the equation '5/12 + 7/16 + 13/x = 1' by finding a common denominator of 48, which gives '20/48 + 21/48 + 13/x = 1'. This simplifies to '41/48 + 13/x = 1'. He then isolates the term with 'x': '13/x = 1 - 41/48 = 7/48'. Solving for 'x' gives 'x = (13 * 48) / 7', which is approximately 88.57, but the instructor notes this is not among the options. He then re-examines the problem and realizes the work done by A and B is not independent. He corrects the approach by using the combined rates: (A+B)'s 5-day work + (B+C)'s 2-day work + C's 11-day work = 1. He writes the equation: '5/12 + 2/16 + 11/x = 1'. He solves this, finding a common denominator of 48, which gives '20/48 + 6/48 + 11/x = 1', or '26/48 + 11/x = 1'. This simplifies to '11/x = 22/48', and solving for 'x' gives 24 days. The video then moves to Question 4, which involves Hari and Giri working together, with Hari leaving after some days and Giri finishing the remaining work in 47 days. The instructor sets up the equation using the LCM method: 'x/70 + (x+47)/60 = 1'. The video ends with a 'THANKS FOR WATCHING' screen.
The video provides a comprehensive tutorial on solving time and work problems by breaking them down into a systematic process. The central theme is the application of the formula: (Time Worked / Time to Complete Alone) = Fraction of Work Done. The instructor demonstrates this principle across four distinct problem types: two individuals working together and one leaving, three individuals with staggered work periods, using combined work rates to find an individual's rate, and using the LCM method for efficient calculation. The progression from simple to more complex problems, coupled with clear, step-by-step algebraic solutions, equips students with a robust methodology for tackling a wide range of time and work questions in competitive exams.