Category 3 Find Day on a Particular Date
Duration: 13 min
This video lesson is available to enrolled students.
AI Summary
An AI-generated summary of this video lecture.
This educational video is a lecture on solving calendar-based problems, a common topic in quantitative aptitude for IT company placements. The instructor, Yash Jain Sir from Knowledge Gate Educator, begins by introducing the concept of finding the day of the week for a given date, using the example of 1st October 2010 being a Monday to find the day for 25th June 2015. He categorizes these problems into four types: (a) Month and Year Same, Date Different; (b) Date and Month Same, Year Different; (c) Date and Year Same, Month Different; and (d) All three different. The main focus is on the third category, where the date and year are the same but the month changes. To solve this, he introduces a method using a 2019 calendar to count the number of odd days between the two months. He demonstrates this by counting the days from January to November 2019, noting that the number of days in each month is either 31 or 30, and that the total number of days from January to November is 334. He then explains that 334 days is equivalent to 47 weeks and 2 days, meaning the day of the week advances by 2 days. The video then presents a specific problem: if 23rd March 2015 is a Tuesday, what day is 23rd November 2015? The instructor applies the same method, counting the days from March to November, which is 244 days, or 34 weeks and 6 days. Since 244 mod 7 = 6, the day advances by 6 days from Tuesday, resulting in Monday. The video concludes with a similar problem from Wipro, where 16th January 1992 is a Monday, and the task is to find the day for 16th December 1992, reinforcing the method for a leap year.
Chapters
0:00 – 2:00 00:00-02:00
The video opens with a title slide showing a calendar and the word 'CALENDAR'. The instructor, Yash Jain Sir, introduces the topic of calendar problems, which are frequently asked in IT company placements. He presents a sample problem: '1st October 2010 → Monday, 25th June 2015 → ???'. He then outlines four categories of such problems, with the first two being 'a) Month and Year Same, Date Different' and 'b) Date and Month Same, Year Different'. The on-screen text clearly labels these categories and provides examples for each.
2:00 – 5:00 02:00-05:00
The instructor continues to explain the four categories of calendar problems. He introduces category 'c) Date and Year Same, Month Different', which is the focus of the current lesson. He provides an example: '1st October 2010 → Monday, 1st December 2010 → ???'. He then transitions to a method for solving this type of problem, which involves counting the number of days between the two months. He displays a 2019 calendar and begins to count the days from January to November, explaining that the number of days in each month is either 31 or 30, and that the total number of days from January to November is 334.
5:00 – 10:00 05:00-10:00
The instructor continues to demonstrate the method for solving calendar problems. He explains that 334 days is equivalent to 47 weeks and 2 days, meaning the day of the week advances by 2 days. He then presents a specific problem from Accenture: 'Suppose if there is Tuesday on 23rd March 2015, then find day on 23rd November 2015?'. He applies the same method, counting the days from March to November, which is 244 days. He explains that 244 days is 34 weeks and 6 days, so the day advances by 6 days from Tuesday. He writes 'Tuesday + 6 days = Monday' on the screen, concluding that 23rd November 2015 is a Monday.
10:00 – 13:16 10:00-13:16
The instructor presents a final problem from Wipro: '16th January 1992 → Monday, 16th December 1992 → ???'. He explains that 1992 is a leap year, which affects the number of days in February. He uses the same method of counting days from January to December, noting that the total number of days is 366. He explains that 366 days is 52 weeks and 2 days, so the day of the week advances by 2 days. He writes 'Monday + 2 days = Wednesday' on the screen, concluding that 16th December 1992 is a Wednesday. The video ends with a 'Thanks for Watching' screen.
The video provides a comprehensive, step-by-step guide to solving calendar problems, a key skill for quantitative aptitude tests. The core of the lesson is a practical method for finding the day of the week when the date and year are the same but the month changes. The instructor systematically breaks down the problem into manageable steps: identifying the category, counting the number of days between the months, calculating the number of odd days (the remainder when divided by 7), and then advancing the day of the week by that number of days. The use of a 2019 calendar as a visual aid makes the counting process clear. The lesson is reinforced with multiple worked examples, including one from Accenture and one from Wipro, demonstrating the method's application to both ordinary and leap years. The progression from a general concept to specific, real-world problems ensures a solid understanding of the technique.