The value of x at which y is minimum for y = x2 − 3x + 1 is

The function y = x^2 - 3x + 1 is a quadratic equation representing a parabola opening upwards. The minimum value occurs at the vertex, where x = -b / (2a). Substituting a = 1 and b = -3, we get x = -(-3) / (2 * 1) = 3/2.