In a three stage counter, using RS flip flops what will be the value of the…
2013
In a three stage counter, using RS flip flops what will be the value of the counter after giving 9 pulses to its input? Assume that the value of counter before giving any pulses is 1.
- A.
1
- B.
2
- C.
9
- D.
10
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Correct answer: B
A three-stage counter using RS flip-flops is a 3-bit binary counter. With 3 bits, the maximum count it can represent is $2^3 - 1 = 7$. This means the counter cycles through values from 0 to 7 and then resets back to 0. The sequence is: 0, 1, 2, 3, 4, 5, 6, 7, 0, 1,...\nThe problem states the initial value is 1. We need to find the value after 9 pulses. Since the counter has a modulus of 8 (counts 0-7), adding 9 pulses is equivalent to adding $9 \pmod 8 = 1$ pulse. Starting from 1, adding 1 results in a value of 2.\nAlternatively, counting step-by-step: Start at 1. Pulse 1 -> 2, Pulse 2 -> 3,..., Pulse 6 -> 7, Pulse 7 -> 0 (reset), Pulse 8 -> 1, Pulse 9 -> 2. Thus, the final value is 2.",