If N2 = (7601)8 where N is a positive integer, then the value of N is
2008
If N2 = (7601)8 where N is a positive integer, then the value of N is
- A.
(241)5
- B.
(143)6
- C.
(165)7
- D.
(39)16
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Correct answer: B
First, convert the octal number (7601)8 to decimal. Calculating 7 times 512 plus 6 times 64 plus 0 plus 1 equals 3969. Second, calculate the square root of 3969 to find N. The result is exactly 63. Third, verify the options by converting them to decimal. Option B (143) base 6 equals 1 times 36 plus 4 times 6 plus 3, which is 63.
N2=(7601)8
N2=7∗83+6∗82+0∗81+1∗80
N2=3969
N=63
Now consider the option
A. (241)5=2∗52+4∗51+1∗50=50+20+1=71(Not an answer)
B. (143)6=1∗62+4∗61+3∗60=36+24+3=63 (Its the answer)
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