If N2 = (7601)8 where N is a positive integer, then the value of N is

2008

If N2 = (7601)8 where N is a positive integer, then the value of N is

  1. A.

    (241)5

  2. B.

    (143)6

  3. C.

    (165)7

  4. D.

    (39)16

Attempted by 116 students.

Show answer & explanation

Correct answer: B

First, convert the octal number (7601)8 to decimal. Calculating 7 times 512 plus 6 times 64 plus 0 plus 1 equals 3969. Second, calculate the square root of 3969 to find N. The result is exactly 63. Third, verify the options by converting them to decimal. Option B (143) base 6 equals 1 times 36 plus 4 times 6 plus 3, which is 63.

N2=(7601)8

N2=7∗83+6∗82+0∗81+1∗80

N2=3969

N=63

Now consider the option

A. (241)5=2∗52+4∗51+1∗50=50+20+1=71(Not an answer)

B. (143)6=1∗62+4∗61+3∗60=36+24+3=63 (Its the answer) 

A video solution is available for this question — log in and enroll to watch it.

Explore the full course: Isro