In Boolean algebra, rule (X+Y)(X+Z) =
2011
In Boolean algebra, rule (X+Y)(X+Z) =
- A.
Y+XZ
- B.
X+YZ
- C.
XY+Z
- D.
XZ+Y
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Correct answer: B
Expand (X+Y)(X+Z) using the distributive law to get XX + XZ + XY + YZ. Apply the idempotent law (XX = X) to simplify to X + XZ + XY + YZ. Factor out X from the first three terms: X(1 + Z + Y) + YZ. Since 1 + A = 1 in Boolean algebra, this becomes X(1) + YZ, which simplifies to the final result: X + YZ.
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