The minimum number of gates required to implement the Boolean expression AB +…
The minimum number of gates required to implement the Boolean expression AB + AB’ + A’C is
Answer: D. 1 OR gate — AB + AB’ + A’C = A (B + B’) + A’C = A(1) + A’C = A + A’C = A + C Therefore, One OR gate.
- A.
1 AND and 1 OR gate
- B.
2 NAND gates
- C.
3 AND gates and 2OR gates
- D.
1 OR gate
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Correct answer: D
AB + AB’ + A’C = A (B + B’) + A’C = A(1) + A’C = A + A’C = A + C
Therefore, One OR gate.
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