K-ary Tree Practice Question 6

Duration: 3 min

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This lecture segment addresses a practice problem involving the calculation of leaf nodes in a full k-ary tree. The instructor begins by defining the problem parameters: a full 5-ary tree containing exactly 26 internal nodes. The core of the lesson focuses on deriving and applying specific formulas that relate the number of internal nodes, leaf nodes, and total edges within a k-ary tree structure. The instructor systematically establishes the relationship between total nodes (n) and internal nodes (I) using the formula n = kI + 1, where k represents the arity of the tree. By substituting the given values (k=5 and I=26), the total number of nodes is calculated as 131. The final step involves isolating the leaf nodes (L) by subtracting the internal nodes from the total node count, yielding a final answer of 105 leaf nodes.

Chapters

  1. 0:00 2:00 00:00-02:00

    The instructor introduces a problem involving a full 5-ary tree with 26 internal nodes and asks to determine the number of leaf nodes. He begins by listing the given values for internal nodes (I) and leaf nodes (L), then writes down a general formula relating total edges to the number of nodes (n-1). The instructor establishes the relationship between total edges and internal nodes, deriving the formula n = kI + 1 to calculate the total number of nodes. The process involves substituting the given values (k=5, I=26) into the derived equation. On-screen text displays 'Q. A full 5-ary tree contains 26 internal nodes' and the instructor writes 'Total edges = n - 1' followed by 'kI = n - 1'. The derivation leads to the equation 'n = kI + 1' with substitution shown as 'n = 5 * 26 + 1'. This section covers the initial setup and formula derivation.

  2. 2:00 2:56 02:00-02:56

    The instructor completes the calculation for total nodes using n = kI + 1, resulting in 131 total nodes. He then uses the relation n = L + I to solve for leaf nodes by subtracting internal nodes from the total. The final calculation shows L = 105. On-screen text confirms 'n = L + I' and the final result 'L = 105'. The instructor demonstrates how to isolate L by rearranging the equation to L = n - I, substituting 131 for n and 26 for I. This section covers the final arithmetic steps and the solution verification.

The lecture effectively demonstrates a standard algorithmic approach for solving k-ary tree problems. The key takeaway is the formula n = kI + 1, which allows students to find total nodes directly from internal nodes without counting edges individually. This formula is derived from the property that every internal node contributes k edges, and total edges equal n-1. The method is robust for any full k-ary tree where internal nodes are known. Students should memorize the relationship n = L + I to easily transition between total, internal, and leaf node counts. The example of a 5-ary tree with 26 internal nodes serves as a concrete application, showing that 131 total nodes minus 26 internal nodes equals 105 leaf nodes. This reinforces the concept that in a full k-ary tree, leaf nodes are significantly more numerous than internal nodes when k > 1.