A fast wide SCSI-II disk drive spins at 7200 RPM, has a sector size of 512…
2011
A fast wide SCSI-II disk drive spins at 7200 RPM, has a sector size of 512 bytes, and holds 160 sectors per track. Estimate the sustained transfer rate of this drive
- A.
576000 Kilobytes / sec
- B.
9600 Kilobytes / sec
- C.
4800 Kilobytes / sec
- D.
19200 Kilobytes / sec
Attempted by 39 students.
Show answer & explanation
Correct answer: B
Convert 7200 RPM to revolutions per second: 7200 / 60 = 120 rev/sec. Calculate bytes per track: 160 sectors * 512 bytes = 81,920 bytes. Multiply rev/sec by bytes/track: 120 * 81,920 = 9,830,400 bytes/sec. Convert to KB using 1 KB = 1024 bytes: 9,830,400 / 1024 = 9600 KB/sec.
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