Consider a 50 kbps satellite channel with a 500 milliseconds round trip…
2014
Consider a 50 kbps satellite channel with a 500 milliseconds round trip propagation delay. If the sender wants to transmit 1000 bit frames, how much time will it take for the receiver to receive the frame?
- A.
250 milliseconds
- B.
20 milliseconds
- C.
520 milliseconds
- D.
270 milliseconds
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Correct answer: D
To determine the total time for the receiver to receive the frame, we calculate the transmission time and propagation delay separately. First, calculate the transmission time (Tt) by dividing the frame size by the bandwidth: Transmission Time = 1000 bits / 50 kbps = 1000 / 50,000 bps = 0.02 seconds = 20 ms. Next, calculate the one-way propagation delay (Tp). Since the round trip time is 500 ms, the one-way delay is half of that: Propagation Delay = 500 ms / 2 = 250 ms. Finally, add the transmission time and propagation delay to find the total reception time: Total Time = 20 ms + 250 ms = 270 ms. Therefore, the receiver receives the frame after 270 milliseconds.
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