Let T(n) be defined by T(1) = 10 and T(n + 1) = 2n + T(n) and for all integers…

2011

Let T(n) be defined by T(1) = 10 and T(n + 1) = 2n + T(n) and for all integers n ≥ 1 . Which of the following represents the order of growth of T(n) as a function of

  1. A.

    O(n)

  2. B.

    O(n log n)

  3. C.

    O(n2)

  4. D.

    O(n3)

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Correct answer: C

To find the order of growth, we expand the recurrence relation T(n + 1) = 2n + T(n). Unrolling this gives T(n) = T(1) + Σ_{i=1}^{n-1} 2i. Given T(1) = 10, we calculate the sum: Σ_{i=1}^{n-1} i = (n-1)n/2. Therefore, T(n) = 10 + 2 * (n-1)n/2 = 10 + n^2 - n. The dominant term is n^2, indicating the order of growth is O(n^2).

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