Let the page fault service time be 10 ms in a computer with average memory…
2016
Let the page fault service time be 10 ms in a computer with average memory access time being 20 ns. If one page fault is generated for every
106 memory accesses, what is the effective access time for the memory?
Answer: B. 29.9 ns — The effective access time (EAT) is calculated using the formula EAT = (1 - p) * T_mem + p * T_fault. Given memory access time T_mem = 20 ns, page fault…
- A.
21.4 ns
- B.
29.9 ns
- C.
23.5 ns
- D.
35.1 ns
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Correct answer: B
The effective access time (EAT) is calculated using the formula EAT = (1 - p) * T_mem + p * T_fault. Given memory access time T_mem = 20 ns, page fault service time T_fault = 10 ms (10^7 ns), and fault rate p = 1/10^6. Substituting these values: EAT ≈ (20 ns) + (10^7 ns * 10^-6) = 20 ns + 10 ns = 30 ns. The closest option is 29.9 ns.
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