A supernet has a first address of 205.16.32.0 and a supernet mask of…

First, convert the subnet mask 255.255.248.0 to CIDR notation. The third octet 248 in binary is 11111000, indicating a /21 prefix. Next, determine the valid IP range. The block size in the third octet is 8 (256 - 248). Starting from 205.16.32.0, the supernet range is 205.16.32.0 to 205.16.39.255. Finally, compare the destination addresses to this range. The address 205.16.39.44 falls within the valid range because its third octet (39) is between 32 and 39. Therefore, this packet belongs to the supernet.