Assume that each character code consists of 8 bits and the asynchronous serial…

Concept: In asynchronous serial transmission, each data character occupies a complete frame. The frame length equals the data bits plus start, stop, and parity bits. Baud counts signal elements per second; with binary signalling, each signal element carries one bit, so 2400 baud provides 2400 bit-times per second.

Application:

1. Find the frame size: 8 data bits + 1 start bit + 2 stop bits + 0 parity bits = 11 bit-times per character.

2. Convert the line rate: binary signalling makes 2400 baud equal to 2400 bit-times per second.

3. Divide the available bit-times by the frame size: 2400 / 11 = 218.18 characters per second.

4. Count only complete frames: floor(218.18) = 218 complete characters per second.

Cross-check: 218 frames require 218 × 11 = 2398 bit-times, which fits within 2400. By contrast, 219 frames require 219 × 11 = 2409 bit-times, which exceeds the available capacity. Therefore the maximum number of complete characters is 218.