An instrument cost a certain factory Rs. 520,000. If it depreciates in value…
2020
An instrument cost a certain factory Rs. 520,000. If it depreciates in value by 16.5% the first year, 15% the next year, 13.5% the third year, and so on, what will be its value (in Rs.) at the end of 8 years, all percentages applying to the original cost?
Answer: D. 52000 — CONCEPT: When each depreciation rate is applied to the original cost, the losses add directly as percentages of that original cost. For rates that form an…
- A.
57500
- B.
65000
- C.
62000
- D.
52000
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Correct answer: D
CONCEPT: When each depreciation rate is applied to the original cost, the losses add directly as percentages of that original cost.
For rates that form an arithmetic sequence, use the arithmetic-series sum to get the total depreciation percentage, then subtract that percentage from 100% to find the remaining value.
APPLICATION:
The 8 yearly rates are 16.5%, 15%, 13.5%, 12%, 10.5%, 9%, 7.5%, and 6%.
Their sum is n/2[2a + (n - 1)d] = 8/2[2(16.5) + 7(-1.5)] = 4(33 - 10.5) = 90%.
So the total depreciation is 90% of Rs. 520,000 = Rs. 468,000.
The value left is Rs. 520,000 - Rs. 468,000 = Rs. 52,000.
CROSS-CHECK: If 90% of the original cost is depreciated, 10% remains; 10% of Rs. 520,000 is Rs. 52,000.
Result: the value at the end of 8 years is Rs. 52,000.
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