The table below has question-wise data on the performance of students in an…

2014

The table below has question-wise data on the performance of students in an examination. The marks for each question are also listed. There is no negative or partial marking in the examination.

\(\begin{array}{|c|c|c|c|c|} \hline \textbf{Q No.} & \textbf{Marks} &\textbf{Answered}&\textbf{Answered}&\textbf{Not}\\&&\textbf{ Correctly} &\textbf{Wrongly} & \textbf{Attempted} \\\hline \text{1} & \text{2} &\text{21} &\text{17} &\text{6}\\\hline \text{2} & \text{3} &\text{15} & \text{27}& \text{2}\\\hline \text{3} & \text{2} &\text{23} & \text{18} & \text{3}\\\hline \end{array}\)

What is the average of the marks obtained by the class in the examination?

Answer: C. 3.02Step 1: Find the total number of students. Each question shows totals 21+17+6 = 44, 15+27+2 = 44, 23+18+3 = 44, so class size = 44 students. Step 2: Find…

  1. A.

    1.34    

  2. B.

    1.74

  3. C.

    3.02

  4. D.

    3.91

Attempted by 27 students.

Show answer & explanation

Correct answer: C

Step 1: Find the total number of students.

Each question shows totals 21+17+6 = 44, 15+27+2 = 44, 23+18+3 = 44, so class size = 44 students.

Step 2: Find total marks obtained by the class.

  • Question 1: marks = 2, correct = 21 ⇒ marks obtained = 2 × 21 = 42.

  • Question 2: marks = 3, correct = 15 ⇒ marks obtained = 3 × 15 = 45.

  • Question 3: marks = 2, correct = 23 ⇒ marks obtained = 2 × 23 = 46.

Total marks obtained = 42 + 45 + 46 = 133.

Step 3: Compute the average marks per student.

Average = total marks / number of students = 133 / 44 = 3.0227… ≈ 3.02

Therefore, the average marks obtained by the class is approximately 3.02.

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