What will be the output of the following pseudocode? integer a, b, c; set a =…

Concept: To find the output of a pseudocode block, execute its statements strictly in the order written, updating each variable's value at every step. For a loop written as "for each X from A to B", the standard convention used across these trace-the-code items is that the loop runs (B minus A) times — i.e. the upper bound is exclusive, matching zero-based counting.

1. Initialize a = 11, b = 12, c = 10.

2. Evaluate if (b > 0): since b = 12 is greater than 0, the condition is true, so the b++ branch runs, not the else branch a++. This makes b = 13; a is still 11.

3. Evaluate for (each b from 0 to 5): this reuses "b" purely as the loop counter, running for 5 iterations (0, 1, 2, 3, 4). On every iteration the statement a = a + 1 executes.

4. After 5 iterations, a = 11 + 5 = 16.

5. Evaluate print(a + c): a + c = 16 + 10 = 26.

Cross-check: reading the loop bound inclusively instead (0 through 5, 6 iterations) would give a = 17 and a print value of 27, but 27 is not among the offered options at all, confirming that the intended (exclusive-upper-bound) reading of 5 iterations, and therefore 26, is correct.