A fuel dealer mixes two brands of fuel which cost in the ratio 2 : 3. A…

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A fuel dealer mixes two brands of fuel which cost in the ratio 2 : 3. A solution containing 30% Brand A and remaining Brand B yields profit of 10% when sold at RS 297. What is cost of brand B?

  1. A.

    300

  2. B.

    208

  3. C.

    262

  4. D.

    354

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Correct answer: A

Key steps:

  1. Compute the cost price (CP) per litre from the selling price (SP) and profit: CP = SP ÷ (1 + profit%) = 297 ÷ 1.10 = 270.

  2. Let the unit costs of Brand A and Brand B be 2c and 3c respectively, since their costs are in the ratio 2:3.

  3. The mixture contains 30% Brand A and 70% Brand B, so the mixture cost per litre = 0.3×(2c) + 0.7×(3c) = 2.7c.

  4. Set this equal to the CP found: 2.7c = 270 ⇒ c = 100.

  5. Therefore the cost of Brand B = 3c = 3×100 = 300.

Answer: 300

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