Deepak went 20 meters to the east. He turned left and walked 15 meters. He…

Concept: In a direction-sense (path-tracking) problem, resolve every leg of the walk onto two perpendicular axes — East-West and North-South. Movements along the same axis in the same direction add together, while movements in opposite directions along the same axis cancel each other. The straight-line distance from the starting point is then found from the net displacement on each axis (using the Pythagorean theorem when both axes have a nonzero net value).

1. Starting direction is East; walk 20 m East. Net position: 20 m East, 0 m North-South.

2. Turning left while facing East means the new heading is North; walk 15 m North. Net position: 20 m East, 15 m North.

3. Turning right while facing North means the new heading is East; walk 35 m East. Net East-West displacement becomes 20 + 35 = 55 m East; North-South stays 15 m North.

4. Turning right while facing East means the new heading is South; walk 15 m South. This is exactly opposite to the earlier 15 m North leg, so it cancels it completely, leaving 0 m net North-South displacement.

Cross-check: since the net North-South displacement is 0, the straight-line distance equals the net East-West displacement directly: the square root of (55 squared plus 0 squared) is 55 m — the same value obtained by simply adding the two eastward legs (20 + 35).

So Deepak is 55 meters from his starting point.