In an exam, Ajith, Sachu, Karna, Saheep and Ramesh scored an average of 39…
2024
In an exam, Ajith, Sachu, Karna, Saheep and Ramesh scored an average of 39 marks. Saheep scored 7 marks more than Ramesh. Ramesh scored 9 fewer than Ajith. Sachu scored as many marks as Saheep and Ramesh scored together. Sachu and Karna scored 110 marks between them. If Ajith scores 32 marks then how many marks did Karna score ?
Answer: C. 57 — For a group of items, the sum of all the items always equals average multiplied by count. When several items are further linked to each other by simple…
- A.
55
- B.
75
- C.
57
- D.
45
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Correct answer: C
For a group of items, the sum of all the items always equals average multiplied by count. When several items are further linked to each other by simple additive relations ("X more than", "X fewer than", or "the sum of two others"), starting from one known value lets every other value be derived in a fixed chain, and the group's average or a partial-sum condition provides the final missing piece once every other member of the chain is known.
The five students' total marks equal average multiplied by count: 39 times 5 equals 195.
Ramesh scored 9 fewer than Ajith, so Ramesh equals 32 minus 9, which is 23.
Saheep scored 7 more than Ramesh, so Saheep equals 23 plus 7, which is 30.
Sachu scored as many as Saheep and Ramesh together, so Sachu equals 30 plus 23, which is 53.
Sachu and Karna together scored 110, so Karna equals 110 minus Sachu, which is 110 minus 53, which is 57.
Adding all five scores independently confirms the chain: 32 (Ajith) plus 23 (Ramesh) plus 30 (Saheep) plus 53 (Sachu) plus 57 (Karna) equals 195, and 195 divided by 5 equals 39, exactly the given average.
So Karna scored 57 marks.
