Rasik walked 20 m towards north. Then he turned right and walked 30 m. Then he…

Concept

In direction-sense (distance-and-direction) problems, plot the walker's path along two perpendicular axes: North-South and East-West. After each turn the facing direction rotates 90 degrees by the turn rule (a right turn is clockwise from the current heading, a left turn is anticlockwise), and every leg's length is added to whichever axis matches the new heading, with opposite headings carrying opposite signs. The final position relative to the start is found by summing the signed displacements on each axis separately, then combining the two net values into one resultant direction and distance.

Step-by-step application

1. Start facing North; walk 20 m North (vertical: +20).

2. Turn right, so North becomes East; walk 30 m East (horizontal: +30).

3. Turn right again, so East becomes South; walk 35 m South (vertical: -35).

4. Turn left, so South becomes East; walk 15 m East (horizontal: +15).

5. Turn left again, so East becomes North; walk 15 m North (vertical: +15).

6. Net vertical displacement = 20 - 35 + 15 = 0. Net horizontal displacement = 30 + 15 = 45 (East).

Cross-check

Since the net vertical displacement is 0, the finishing point lies directly along the East-West line through the start, so the resultant distance equals the net horizontal displacement itself, with no diagonal combination needed. Plotting all five legs on a grid confirms the same endpoint, 45 m to the east of the starting point.

Result: Rasik is 45 m to the East of his starting position.