What is the regular expression for the language generated by S → aS | bA A → d…
What is the regular expression for the language generated by
S → aS | bA
A → d | ccA
Answer: C. a* b(cc)* d — The grammar S → aS | bA and A → d | ccA generates strings that start with zero or more 'a's, followed by a 'b', then zero or more occurrences of 'cc', and…
- A.
a*bd
- B.
a* (bd)(bcc)* d
- C.
a* b(cc)* d
- D.
None of these
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Correct answer: C
The grammar S → aS | bA and A → d | ccA generates strings that start with zero or more 'a's, followed by a 'b', then zero or more occurrences of 'cc', and ending with 'd'. This corresponds to the regular expression a* b(cc)* d. Option C correctly represents this pattern.
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