A demand paging system takes 100 time units to service a page fault and 300…
GATE · 2007 · ITModified — slightly modified from the official paper; see the solution
A demand paging system takes 100 time units to service a page fault and 300 time units to replace a dirty page. Memory access time is 1 time unit. The probability of a page fault is p. In case of a page fault, the probability of page being dirty is also p. It is observed that the average access time is 3 time units. Then the value of p is
- A.
0.0194
- B.
0.233
- C.
0.514
- D.
0.981
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