For the clock shown in the figure, if O* = O Q S Z P R T, and X* = X Z P W Y O…

Treat the dial as a 12‑step clock read clockwise from the top, assigning indices O=0, P=1, Q=2, R=3, S=4, T=5, U=6, V=7, W=8, X=9, Y=10, Z=11. Examine the given strings as index sequences. O* = O Q S Z P R T gives 0,2,4,11,1,3,5, whose successive clockwise gaps are +2,+2,+7,+2,+2,+2. X* = X Z P W Y O Q gives 9,11,1,8,10,0,2, with the same gap pattern +2,+2,+7,+2,+2,+2. So the rule is: a first block of three letters each +2 apart, then one bridge jump of +7 (equivalently the second block begins at index −1 mod 12 from the start letter), then a second block of four letters each +2 apart. Apply it to P (index 1). First block: 1,3,5 → P, R, T. Bridge to index 0 and continue +2: 0,2,4,6 → O, Q, S, U. Concatenating gives P* = P R T O Q S U.