If the list of letters, P, R, S, T, U is an arithmetic sequence, which of the…
2015
If the list of letters, P, R, S, T, U is an arithmetic sequence, which of the following are also in arithmetic sequence?
I. 2P, 2R, 2S, 2T, 2U
II. P-3, R-3, S-3, T-3, U-3
III. P2, R2, S2, T2, U2
- A.
I only
- B.
I and II
- C.
II and III
- D.
I and III
Attempted by 58 students.
Show answer & explanation
Correct answer: B
Key idea: Multiplying all terms by the same constant or adding/subtracting the same constant preserves the common difference; squaring does not generally preserve it.
Write the terms of the arithmetic sequence as P, P + d, P + 2d, P + 3d, P + 4d, where d is the common difference.
Multiplying each term by 2 gives 2P, 2(P + d), 2(P + 2d), … The difference between consecutive terms is 2d, so these terms form an arithmetic sequence.
Subtracting 3 from each term gives P − 3, (P + d) − 3, (P + 2d) − 3, … The differences remain d, so these terms also form an arithmetic sequence.
Squaring the terms gives (P + kd)^2 for k = 0, 1, 2, 3, 4. The difference between consecutive squared terms equals
(P + (k + 1)d)^2 − (P + kd)^2 = 2Pd + (2k + 1)d^2, which depends on k unless d = 0. Therefore the differences are not constant in general.
Concrete counterexample: choose P = 1 and d = 2 so the arithmetic sequence is 1, 3, 5, 7, 9. Squaring gives 1, 9, 25, 49, 81 with consecutive differences 8, 16, 24, 32, which are not constant.
Conclusion: Multiplying all terms by 2 and subtracting 3 both preserve an arithmetic sequence, but squaring does not in general. Therefore the transformations that multiply all terms by 2 and subtract 3 produce arithmetic sequences.