If the list of letters, P, R, S, T, U is an arithmetic sequence, which of the…

2015

If the list of letters, P, R, S, T, U is an arithmetic sequence, which of the following are also in arithmetic sequence?

I. 2P, 2R, 2S, 2T, 2U

II. P-3, R-3, S-3, T-3, U-3

III. P2, R2, S2, T2, U2

  1. A.

    I only

  2. B.

    I and II

  3. C.

    II and III

  4. D.

    I and III

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Show answer & explanation

Correct answer: B

Key idea: Multiplying all terms by the same constant or adding/subtracting the same constant preserves the common difference; squaring does not generally preserve it.

  • Write the terms of the arithmetic sequence as P, P + d, P + 2d, P + 3d, P + 4d, where d is the common difference.

  • Multiplying each term by 2 gives 2P, 2(P + d), 2(P + 2d), … The difference between consecutive terms is 2d, so these terms form an arithmetic sequence.

  • Subtracting 3 from each term gives P − 3, (P + d) − 3, (P + 2d) − 3, … The differences remain d, so these terms also form an arithmetic sequence.

  • Squaring the terms gives (P + kd)^2 for k = 0, 1, 2, 3, 4. The difference between consecutive squared terms equals

  • (P + (k + 1)d)^2 − (P + kd)^2 = 2Pd + (2k + 1)d^2, which depends on k unless d = 0. Therefore the differences are not constant in general.

  • Concrete counterexample: choose P = 1 and d = 2 so the arithmetic sequence is 1, 3, 5, 7, 9. Squaring gives 1, 9, 25, 49, 81 with consecutive differences 8, 16, 24, 32, which are not constant.

Conclusion: Multiplying all terms by 2 and subtracting 3 both preserve an arithmetic sequence, but squaring does not in general. Therefore the transformations that multiply all terms by 2 and subtract 3 produce arithmetic sequences.

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