The determinant of the matrix [Tex]\begin{bmatrix} 6 & -8 & 1 & 1 \\ 0 & 2 & 4…

For a triangular matrix — upper or lower — every entry on one side of the main diagonal is zero. Expanding the determinant by cofactors along the first column of an upper triangular matrix leaves only the cofactor of the top-left diagonal entry nonzero, since every other entry in that column is zero; repeating this reduction row by row shows that the determinant of any triangular matrix equals the product of its diagonal entries.

In the given matrix, every entry below the main diagonal is zero, so it is upper triangular, with diagonal entries 6, 2, 4, and -1. Its determinant is their product, computed step by step:

1. 6 × 2 = 12

2. 12 × 4 = 48

3. 48 × (-1) = -48

As an independent cross-check, expand along the last row, which has only one nonzero entry, -1, in the bottom-right position. Its cofactor is the determinant of the top-left 3 × 3 block, itself upper triangular with diagonal entries 6, 2, and 4, giving 6 × 2 × 4 = 48; the cofactor sign at that position is positive, so the determinant is (-1) × 48 = -48, matching the direct product.

The determinant of the matrix is -48.