For any twice differentiable function 𝑓: ℝ β†’ ℝ, if at some π‘₯βˆ— ∈ ℝ, 𝑓′ (π‘₯βˆ—β€¦

2024

For any twice differentiable function 𝑓: ℝ β†’ ℝ, if at some π‘₯βˆ— ∈ ℝ, 𝑓′ (π‘₯βˆ— ) = 0 and 𝑓′′(π‘₯βˆ— ) > 0, then the function 𝑓 necessarily has a ______ at π‘₯ = π‘₯βˆ— .

Note: ℝ denotes the set of real numbers.

  1. A.

    local minimum

  2. B.

    global minimum

  3. C.

    local maximum

  4. D.

    global maximum

Show answer & explanation

Correct answer: A

Key idea: use the second derivative test. Since fβ€²(x*) = 0, x* is a critical point. Since fβ€²β€²(x*) > 0, the graph is concave up near x*. Using the local Taylor expansion, f(x) β‰ˆ f(x*) + (1/2)fβ€²β€²(x*)(x βˆ’ x*)Β² near x*. The quadratic term is positive for x close to x* and x β‰  x*, so nearby values of f(x) are greater than f(x*). Therefore, f has a local minimum at x = x*. This condition does not by itself guarantee a global minimum.

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