For any twice differentiable function π: β β β, if at some π₯β β β, πβ² (π₯ββ¦
2024
For any twice differentiable function π: β β β, if at some π₯β β β, πβ² (π₯β ) = 0 and πβ²β²(π₯β ) > 0, then the function π necessarily has a ______ at π₯ = π₯β .
Note: β denotes the set of real numbers.
- A.
local minimum
- B.
global minimum
- C.
local maximum
- D.
global maximum
Show answer & explanation
Correct answer: A
Key idea: use the second derivative test. Since fβ²(x*) = 0, x* is a critical point. Since fβ²β²(x*) > 0, the graph is concave up near x*. Using the local Taylor expansion, f(x) β f(x*) + (1/2)fβ²β²(x*)(x β x*)Β² near x*. The quadratic term is positive for x close to x* and x β x*, so nearby values of f(x) are greater than f(x*). Therefore, f has a local minimum at x = x*. This condition does not by itself guarantee a global minimum.