Consider the function 𝑓:ℝ→ℝ defined as follows: where 𝑐1 ,𝑐2βˆˆβ„. If 𝑓 is…

2026

Consider the function 𝑓:ℝ→ℝ defined as follows:

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where 𝑐1 ,𝑐2βˆˆβ„.

If 𝑓 is continuous at π‘₯ = 0, then 𝑐1+𝑐2 = _________. (answer in integer)

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Correct answer: 3

For x ≀ 0, f(x) = 3, so f(0) = 3 and the left-hand limit at 0 is 3. For x > 0, f(x) = c₁eΛ£ - cβ‚‚ ln(1/x). As x β†’ 0+, ln(1/x) β†’ ∞. For the right-hand limit to be finite, we must have cβ‚‚ = 0. Then the right-hand limit becomes c₁e⁰ = c₁. Continuity at x = 0 requires c₁ = 3. Hence c₁ + cβ‚‚ = 3 + 0 = 3.

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