Consider the function π:βββ defined as follows: where π1 ,π2ββ. If π isβ¦
2026
Consider the function π:βββ defined as follows:

where π1 ,π2ββ.
If π is continuous at π₯ = 0, then π1+π2 = _________. (answer in integer)
Show answer & explanation
Correct answer: 3
For x β€ 0, f(x) = 3, so f(0) = 3 and the left-hand limit at 0 is 3. For x > 0, f(x) = cβeΛ£ - cβ ln(1/x). As x β 0+, ln(1/x) β β. For the right-hand limit to be finite, we must have cβ = 0. Then the right-hand limit becomes cβeβ° = cβ. Continuity at x = 0 requires cβ = 3. Hence cβ + cβ = 3 + 0 = 3.