Which one of the following functions is continuous at \(x\) = 3?

2013

Which one of the following functions is continuous at \(x\) = 3?

  1. A.

    \(f(x) = \begin{cases} 2,&\text{if $x = 3$ } \\ x-1& \text{if $x > 3$}\\ \frac{x+3}{3}&\text{if $x < 3$ } \end{cases}\)

  2. B.

    \(f(x) = \begin{cases} 4,&\text{if $x = 3$ } \\ 8-x& \text{if $x \neq 3$} \end{cases}\)

  3. C.

    \(f(x) = \begin{cases} x+3,&\text{if $x \leq 3$ } \\ x-4& \text{if $x > 3$} \end{cases}\)

  4. D.

    \(f(x) = \begin{cases} \frac{1}{x^3-27}&\text{if $x \neq 3$ } \end{cases}\)

Attempted by 47 students.

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Correct answer: A

How to check continuity at x = 3:

  • Compute the left-hand limit using f(x) = (x+3)/3 for x < 3: (3+3)/3 = 2.

  • Compute the right-hand limit using f(x) = x − 1 for x > 3: 3 − 1 = 2.

  • Evaluate the function at x = 3: f(3) = 2.

  • Conclusion: left-hand limit = right-hand limit = function value = 2, so the function is continuous at x = 3.

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