Consider the binary relation: S = {(x, y) | y = x+1 and x, y ∈ {0, 1, 2, ...}}…
GATE · 2004 · CS
Consider the binary relation:
S = {(x, y) | y = x+1 and x, y ∈ {0, 1, 2, ...}}The reflexive transitive closure of S is
- A.
{(x, y) | y > x and x, y ∈ {0, 1, 2, ... }}
- B.
{(x, y) | y ≥ x and x, y ∈ {0, 1, 2, ... }}
- C.
{(x, y) | y < x and x, y ∈ {0, 1, 2, ... }}
- D.
{(x, y) | y ≤ x and x, y ∈ {0, 1, 2, ... }}
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