Let a, b, c, and d be propositions. Assume that the equivalences a ↔ (b ∨ ¬b)…

2000

Let a, b, c, and d be propositions. Assume that the equivalences a ↔ (b ∨ ¬b) and b ↔ c hold. Then the truth value of the formula ((a ∧ b) → ((a ∧ c) ∨ d)) is always:

  1. A.

    True

  2. B.

    False

  3. C.

    Same as the truth value of b

  4. D.

    Same as the truth value of d

Attempted by 20 students.

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Correct answer: A

The expression b ∨ ¬b is a tautology, so a ↔ (b ∨ ¬b) forces a to be true.

The condition b ↔ c means b and c always have the same truth value.

Now simplify the formula: ((a ∧ b) → ((a ∧ c) ∨ d)). Since a is true, this becomes b → (c ∨ d). Since c has the same truth value as b, it becomes b → (b ∨ d).

If b is true, then b ∨ d is true. If b is false, the implication is true vacuously. Therefore the formula is always true.

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