In propositional logic P ↔ Q is equivalent to (Where ~ denotes NOT)
2015
In propositional logic P ↔ Q is equivalent to (Where ~ denotes NOT)
- A.
~(P ∨ Q) ∧ ~(Q ∨ P)
- B.
(~P ∨ Q) ∧ (~Q ∨ P)
- C.
(P ∨ Q) ∧ (Q ∨ P)
- D.
~(P ∨ Q) → ~(Q ∨ P)
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Correct answer: B
To find which expression is equivalent to P ↔ Q, let's first break down the standard definition of a biconditional (two-way) implication.
By definition: P ↔ Q ≡ (P → Q)∧(Q → P)
Using the implication elimination rule (A → B ≡ ¬A ∨ B), we can rewrite both individual conditional statements:
P → Q ≡ ¬P ∨ Q
Q → P ≡ ¬Q ∨ P
Substituting these back into the conjunction gives:
P → Q ≡ (¬P ∨ Q)∧ (¬Q ∨ P)
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