In propositional logic P ↔ Q is equivalent to (Where ~ denotes NOT)

2015

In propositional logic P ↔ Q is equivalent to (Where ~ denotes NOT)

  1. A.

    ~(P ∨ Q) ∧ ~(Q ∨ P)

  2. B.

    (~P ∨ Q) ∧ (~Q ∨ P)

  3. C.

    (P ∨ Q) ∧ (Q ∨ P)

  4. D.

    ~(P ∨ Q) → ~(Q ∨ P)

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Correct answer: B

To find which expression is equivalent to P Q, let's first break down the standard definition of a biconditional (two-way) implication.

By definition: P Q (P → Q)∧(Q → P)

Using the implication elimination rule (A B ¬A B), we can rewrite both individual conditional statements:

P Q ¬P Q

Q P ¬Q ∨ P

Substituting these back into the conjunction gives:

P → Q ≡ (¬P ∨ Q)∧ (¬Q ∨ P)

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