G is a simple undirected graph. Some vertices of G are of odd degree. Add a…

2008

G is a simple undirected graph. Some vertices of G are of odd degree. Add a node v to G and make it adjacent to each odd degree vertex of G. The resultant graph is sure to be

  1. A.

    regular

  2. B.

    Complete

  3. C.

    Hamiltonian

  4. D.

    Euler

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Correct answer: D

Answer: Euler. The resulting graph is Eulerian because every vertex has even degree.

  • By the Handshaking Lemma, the number of vertices of odd degree in any graph is even.

  • Joining the new vertex to every odd-degree vertex increases each odd degree by 1, making those degrees even. Vertices that were even remain even.

  • The new vertex has degree equal to the number of odd-degree vertices, which is even, so its degree is even as well.

  • Therefore every vertex in the resulting graph has even degree, so the graph is Eulerian (each connected component has an Euler circuit).

Why the other answers are incorrect:

  • Not necessarily regular: degrees become even but need not be equal across vertices.

  • Not necessarily complete: no new edges are added between existing vertex pairs, so completeness is not guaranteed.

  • Not necessarily Hamiltonian: even degrees do not ensure a Hamiltonian cycle.

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