Consider the equation \((123)_5 = (x8)_y\) with \(x\) and \(y\) as unknown.…
2014
Consider the equation \((123)_5 = (x8)_y\) with \(x\) and \(y\) as unknown. The number of possible solutions is _____ .
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Correct answer: 3
Convert the base-5 number to decimal:
(123) in base 5 equals 1×25 + 2×5 + 3 = 25 + 10 + 3 = 38
We need a base-y two-digit number with digits x and 8 to equal 38, so:
x·y + 8 = 38, therefore x·y = 30.
Constraints:
The base y must be greater than 8 (so that digit 8 is valid).
x must be an integer with 0 ≤ x < y.
Find integer factor pairs of 30 with y > 8 and x < y:
x = 1, y = 30 → valid (30 > 8 and 1 < 30).
x = 2, y = 15 → valid (15 > 8 and 2 < 15).
x = 3, y = 10 → valid (10 > 8 and 3 < 10).
Other factor pairs either have base y ≤ 8 or do not satisfy x < y, so they are invalid.
Therefore, the number of possible solutions is 3.
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