Let A = 1111 1010 arid B = 0000 1010 be two 8-bit 2's complement numbers.…
2004
Let A = 1111 1010 arid B = 0000 1010 be two 8-bit 2's complement numbers. Their product in 2's complement is
- A.
1100 0100
- B.
1001 1100
- C.
1010 0101
- D.
1101 0101
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Correct answer: A
Step 1: Convert each 8-bit two's complement operand to decimal.
1111 1010 → invert bits → 0000 0101 (5), add 1 → 0000 0110 (6) → value = -6.
0000 1010 → already positive → value = +10.
Step 2: Multiply the decimal values.
-6 × 10 = -60.
Step 3: Convert -60 to 8-bit two's complement.
Start with +60: 0011 1100.
Invert bits → 1100 0011. Add 1 → 1100 0100.
Result: 1100 0100
Therefore, the product of 1111 1010 and 0000 1010 in 8-bit two's complement representation is 1100 0100.