Consider the circuit in below figure. f implements

1996

Consider the circuit in below figure. f implements

image.png

  1. A.

    (ABC)′+A′BC′+ABC

  2. B.

    A+B+C

  3. C.

    A⊕B⊕C

  4. D.

    AB+BC+CA

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Correct answer: C

To determine which boolean function the 4-to-1 Multiplexer (Mux) implements, we can derive its output equation based on the select lines and input lines.

Step-by-Step Derivation

A 4-to-1 multiplexer selects one of its four data inputs (I0, I1, I2, I3) based on the binary combination of its select lines (S1, S0).

From the given circuit diagram:

  • Select lines: S1 = A, S0 = B

  • Data inputs:

    • I0 = C

    • I1 = ~C

    • I2 = ~C

    • I3 = C

The general characteristic equation for a 4-to-1 Mux is:

Substituting our specific values into the equation:

Simplifying the Expression

Let's group the terms to recognize standard logic gates:

  1. Grouping the first and last terms, and the middle two terms:

  2. Recognize the standard XOR and XNOR relations:

  3. Substitute these back into the expression:

  4. Let Y = A B. The expression becomes:

    f = (~Y)C + Y(~C)

    This is the exact definition of an XOR operation between $Y$ and $C$:

    f = Y ⊕ C

  5. Substitute Y = A B back in:

    f = A ⊕ B ⊕ C

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