Given the following Karnaugh Map for a Boolean function πΉ(π€, π₯, π¦, π§):β¦
2025
Given the following Karnaugh Map for a Boolean function πΉ(π€, π₯, π¦, π§):

Which one or more of the following Boolean expression(s) represent(s) πΉ?
- A.
\(\bar{w} \bar{x} \bar{y} \bar{z}+w \bar{x} \bar{y} \bar{z}+\bar{w} \bar{x} y \bar{z}+w \bar{x} y \bar{z}+x z\) - B.
\(\bar{w} \bar{x} \bar{y} \bar{z}+\bar{w} \bar{x} y \bar{z}+w \bar{x} y z+x z\) - C.
\(\bar{w} \bar{x} \bar{y} \bar{z}+w \bar{x} \bar{y} \bar{z}+w \bar{x} \bar{y} z+x z\) - D.
\(\bar{x} \bar{z}+x z\)
Attempted by 140 students.
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Correct answer: A, D
Step 1: Find groups of 1s on the Karnaugh map and identify common variables.
Group of four covering cells where x = 0 and z = 0 (w and y vary): these four minterms are \bar{w}\bar{x}\bar{y}\bar{z}, w\bar{x}\bar{y}\bar{z}, \bar{w}\bar{x}y\bar{z}, w\bar{x}y\bar{z} which simplify to \bar{x}\bar{z}.
Group of four covering cells where x = 1 and z = 1 (w and y vary): these minterms combine to x z.
Step 2: Write the simplified function by OR-ing the group results.
F(w,x,y,z) = \bar{x}\bar{z} + x z
Note: The expanded expression \bar{w}\bar{x}\bar{y}\bar{z} + w\bar{x}\bar{y}\bar{z} + \bar{w}\bar{x}y\bar{z} + w\bar{x}y\bar{z} + x z is algebraically equivalent to \bar{x}\bar{z} + x z because the four minterms shown collapse to \bar{x}\bar{z}.
Tip: To check any proposed expression, expand it into minterms and verify each minterm against the 1-cells of the K-map; any minterm present in the expression must correspond to a 1-cell, and every 1-cell must be covered by at least one term.
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