Consider the following New-order strategy for traversing a binary tree: Visit…

Solution: Build the expression tree from the given postfix (RPN) expression 3 4 * 5 - 2 ˆ 6 7 * 1 + - and then apply New-order traversal (visit root, then right subtree, then left subtree).

Step 1 — Parse the postfix expression into a tree (stack method):

• Push 3, push 4. On '*', pop 4 (right) and 3 (left) → node (* 3 4).

• Push 5. On '-', pop 5 (right) and (* 3 4) (left) → node (- (* 3 4) 5).

• Push 2. On 'ˆ', pop 2 (right) and the previous '-' node (left) → node (ˆ (- (* 3 4) 5) 2).

• Push 6, push 7. On '*', pop 7 (right) and 6 (left) → node (* 6 7).

• Push 1. On '+', pop 1 (right) and (* 6 7) (left) → node (+ (* 6 7) 1).

• Finally on '-', pop the '+' node (right) and the 'ˆ' node (left) → root node (- (ˆ ...) (+ ...)).

Step 2 — Summary of the resulting tree structure:

Root is '-', right subtree is '+' (left child '*' with 6 and 7, right child 1), left subtree is 'ˆ' (left child '-' which has '*' with 3 and 4 and right child 5, and right child 2).

Step 3 — Apply New-order traversal (root, right, left):

• Visit root: -

• Traverse right subtree '+' in New-order: visit '+', then its right child 1, then its left child '*' (visit '*', then right 7, then left 6) → + 1 * 7 6

• Traverse left subtree 'ˆ' in New-order: visit 'ˆ', then its right child 2, then its left child '-' (visit '-', then right 5, then left '*' (visit '*', then right 4, then left 3)) → ˆ 2 - 5 * 4 3

Combine the parts (root, right-subtree result, left-subtree result):

Final New-order traversal: - + 1 * 7 6 ˆ 2 - 5 * 4 3