For the network given in the figure below, the routing tables of the four…

Approach: Use distance-vector update: for each destination, compute cost via each neighbor as (cost from F to that neighbor) + (neighbor's reported cost to destination), then choose the minimum.

Given:

• Neighbors and link costs: A = 8 ms, E = 10 ms, D = 12 ms, G = 6 ms.

• Relevant entries from neighbors' routing tables (as given):

  • A: A=0, B=40, C=14, D=17, E=21, F=9, G=24

  • D: A=20, B=8, C=30, D=0, E=14, F=7, G=22

  • E: A=24, B=10, C=7, D=20, E=0, F=11, G=22

  • G: A=21, B=14, C=11, D=22, E=19, F=10, G=0

Compute updated costs for F:

• To A: via A = 8 + 0 = 8; via E = 10 + 24 = 34; via D = 12 + 20 = 32; via G = 6 + 21 = 27 → choose 8 (via A).

• To B: via A = 8 + 40 = 48; via E = 10 + 10 = 20; via D = 12 + 8 = 20; via G = 6 + 14 = 20 → choose 20 (via D or E or G).

• To C: via A = 8 + 14 = 22; via E = 10 + 7 = 17; via D = 12 + 30 = 42; via G = 6 + 11 = 17 → choose 17 (via E or G).

• To D: via A = 8 + 17 = 25; via E = 10 + 20 = 30; via D = 12 + 0 = 12; via G = 6 + 22 = 28 → choose 12 (via D).

• To E: via A = 8 + 21 = 29; via E = 10 + 0 = 10; via D = 12 + 14 = 26; via G = 6 + 19 = 25 → choose 10 (via E).

• To G: via A = 8 + 24 = 32; via E = 10 + 22 = 32; via D = 12 + 22 = 34; via G = 6 + 0 = 6 → choose 6 (via G).

• To F: distance to self = 0.

Final updated routing table for F (costs):

• A: 8

• B: 20

• C: 17

• D: 12

• E: 10

• F: 0

• G: 6

Therefore the table shown in option A matches the computed updated routing table for F.