What is the output?
#include
int main()
{
int i, j, *ptr, *ptr1;
i =10;
j =10;
ptr =&i;
ptr1 = &j;
if(ptr ==ptr1)
{
printf(“True”);
}
else
{
printf(“False”);
}
}

Question

What is the output? #include int main() { int i, j, *ptr, *ptr1; i =10; j =10; ptr =&i; ptr1 = &j; if(ptr ==ptr1) { printf(“True”); } else { printf(“False”); } }

Accepted Answer

Correct answer: D — The condition compares the addresses stored in ptr and ptr1, not the values they point to. Since ptr points to variable i and ptr1 points to variable j, and i and j are different variables, their addresses are different. Therefore, the condition ptr == ptr1 evaluates to false, and the else block executes, printing 'False'.

Answer

A. True

Answer

B. Compiler error

Answer

C. No output

Answer

D. False

What is the output? #include int main() { int i, j, *ptr, *ptr1; i =10; j =10;…

What is the output? #include int main() { int i, j, ptr, ptr1; i =10; j =10;…