What will be the output of following program?
#include <stdio.h>
int main() {
char s1[7] = "abcd";
char *p;

p = s1 + 2;
*p = 'e';
printf("%s", s1);
return 0;
}

Question

What will be the output of following program? #include <stdio.h> int main() { char s1[7] = "abcd"; char *p; p = s1 + 2; *p = 'e'; printf("%s", s1); return 0; }

Accepted Answer

Correct answer: C — Answer: C) abed Explanation: Initial String: s1 stores the string "abcd". Pointer Setup: p = s1 + 2; makes the pointer p point directly to the third character in the string, which is 'c' (at index 2). Modification: *p = 'e'; modifies the value at that exact memory location, overwriting 'c' with 'e'. Consequently, the string changes from "abcd" to abed.

Answer

A. abcde

Answer

B. abd

Answer

C. abed

Answer

D. abcd0e

What will be the output of following program? #include <stdio.h> int main() {…