If tan θ + sec θ = 4, then the value of cos θ is equal to :
2024
If tan θ + sec θ = 4, then the value of cos θ is equal to :
- A.
17/8
- B.
8/17
- C.
15/17
- D.
17/15
Attempted by 4 students.
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Correct answer: B
Given: tan θ + sec θ = 4.
We use the identity: sec²θ - tan²θ = 1.
Let tan θ + sec θ = 4 and tan θ - sec θ = x.
Multiply both equations: (tan θ + sec θ)(tan θ - sec θ) = 4x.
This gives: tan²θ - sec²θ = 4x.
But tan²θ - sec²θ = -1, so -1 = 4x → x = -1/4.
Now solve the system: tan θ + sec θ = 4 and tan θ - sec θ = -1/4.
Add the two equations: 2 tan θ = 15/4 → tan θ = 15/8.
Now use tan θ = sin θ / cos θ and sin²θ + cos²θ = 1.
Let sin θ = 15k and cos θ = 8k.
Then (15k)² + (8k)² = 1 → 225k² + 64k² = 1 → 289k² = 1 → k² = 1/289 → k = 1/17.
Therefore, cos θ = 8k = 8/17.
हिन्दी उत्तर:
दिया गया है: tan θ + sec θ = 4।
हम पहचान का उपयोग करते हैं: sec²θ - tan²θ = 1।
मान लीजिए tan θ + sec θ = 4 और tan θ - sec θ = x।
दोनों समीकरणों को गुणा करें: (tan θ + sec θ)(tan θ - sec θ) = 4x।
इससे प्राप्त होता है: tan²θ - sec²θ = 4x।
लेकिन tan²θ - sec²θ = -1, इसलिए -1 = 4x → x = -1/4।
अब निम्न समीकरणों का समाधान करें: tan θ + sec θ = 4 और tan θ - sec θ = -1/4।
दोनों समीकरणों को जोड़ें: 2 tan θ = 15/4 → tan θ = 15/8।
अब tan θ = sin θ / cos θ और sin²θ + cos²θ = 1 का उपयोग करें।
मान लीजिए sin θ = 15k और cos θ = 8k।
तब (15k)² + (8k)² = 1 → 225k² + 64k² = 1 → 289k² = 1 → k² = 1/289 → k = 1/17।
इसलिए, cos θ = 8k = 8/17।