What is the minimum value of function y = x2 in the interval [1, 6] ?
2021
What is the minimum value of function y = x2 in the interval [1, 6] ?
Answer: B. 1 — Given y = x² Differentiate: dy/dx = 2x For every x in [1, 6], 2x > 0 Therefore, y = x² is strictly increasing on [1, 6]. For an increasing function on a…
- A.
2
- B.
1
- C.
3
- D.
4
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Correct answer: B
Given
y = x²
Differentiate:
dy/dx = 2x
For every x in [1, 6],
2x > 0
Therefore, y = x² is strictly increasing on [1, 6].
For an increasing function on a closed interval, the minimum value occurs at the left endpoint.
So,
x = 1
and
y = 1² = 1
Answer
1 (Option B) ✅
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