Study the given information carefully and answer the given question. Asha,…

In a circular-seating-plus-coded-series puzzle, first turn every ‘X is nth to the right of Y’ clue into a fixed forward seat-count along one consistent rotational direction (everyone faces the centre, so ‘right’ is one fixed sense), and solve all the clues together to fix a single seating order. Once the order is fixed, work out what fixed relationship each written pair in the given series encodes and how the starting name shifts from one pair to the next, so the same rule extends to the missing pair.

1. Fix a rightward seat count starting from Asha (seat 0), and use ‘Gita is third to the right of Fita’ together with the neighbour restrictions (‘Hema is not an immediate neighbour of Fita or Gita’, ‘Chitra is not an immediate neighbour of Gita’, ‘Deena is not an immediate neighbour of Hema or Chitra’) and the two remaining offsets (‘Asha is second to the right of Hema’, ‘Bina is third to the right of Chitra’) to solve for one consistent order. This fixes everyone’s seat as, going rightward from Asha: Asha, Fita, Bina, Deena, Gita, Ena, Hema, Chitra, then back to Asha.

2. Check every clue against this order: Fita (seat 1) + 3 seats = Gita (seat 4); Hema (seat 6) is not next to Fita (seats 0, 2) or Gita (seats 3, 5); Hema (seat 6) + 2 seats = Asha (seat 0, wrapping round); Chitra (seat 7) + 3 seats = Bina (seat 2); Chitra is not next to Gita; Deena (seat 3) is not next to Hema (seats 5, 7) or Chitra (seats 6, 0). Every condition holds, so this order is the unique fit.

3. Read the given series in two-name blocks: Asha-Fita, Deena-Gita, Chitra-Asha, and the incomplete final block. In every complete block, the second name is exactly the seat-neighbour immediately to the right of the first name (Fita is to Asha’s right, Gita is to Deena’s right, Asha is to Chitra’s right).

4. Track how far the opening name of each block sits from the opening name of the block before it, counting seats rightward: Asha (seat 0) to Deena (seat 3) is 3 seats; Deena (seat 3) to Chitra (seat 7) is 4 seats — the seat-gap between successive opening names grows by one seat each time it is applied.

5. Extend that growing gap once more: the next opening name must sit 5 seats to the right of Chitra (seat 7), i.e. at seat (7 + 5) mod 8 = seat 4, which is Gita’s seat.

6. Pair this opening name with the seat-neighbour immediately to its right — the same rule used in every earlier block — to complete the final block.

Cross-check with the cumulative sum instead of chaining: adding the three growing gaps directly to Asha’s seat gives 0 + 3 + 4 + 5 = 12, and 12 mod 8 = 4 — the same seat reached by chaining gap after gap. The two ways of computing the shift agree, confirming the missing block’s opening name and, through the fixed right-neighbour rule, its paired name too.

The missing block is therefore Gita paired with the person seated immediately to her right, Ena — matching ‘Gita - Ena’.