Raghu got the 20th rank among all the students in the class. How many students…

2023

Raghu got the 20th rank among all the students in the class. How many students are there in the class?

  1. Rajive ranked second-last among all.

  2. Rajive ranked next to Raghu.

  1. A.

    Statement 1 alone is sufficient to solve the problem

  2. B.

    Both statements put together are sufficient to solve the problem

  3. C.

    Both statements even put together are not sufficient to solve the problem

  4. D.

    Statement 2 alone is sufficient to solve the problem

Show answer & explanation

Correct answer: C

Concept: In a rank-based data-sufficiency problem, a student's rank counted from the top (R_top) and rank counted from the bottom (R_bottom) in a class of N students are linked by the identity N = R_top + R_bottom - 1. The class size N is uniquely determined ONLY IF every rank-pair (R_top, R_bottom) admitted by the given statements yields the SAME value of R_top + R_bottom - 1; if different admissible pairs give different sums, N is left undetermined even though each individual statement may look informative.

Application:

  1. Statement 1 alone: "second-last" fixes only Rajive's rank from the bottom, R_bottom(Rajive) = 2. It gives no rank from the top and no link to Raghu at all, so N cannot be computed from it alone.

  2. Statement 2 alone: "next to Raghu" only relates Rajive's rank from the top to Raghu's rank (20), giving two candidates: R_top(Rajive) = 19 or R_top(Rajive) = 21. It says nothing about Rajive's distance from the bottom, so N still cannot be computed from it alone.

  3. Both together: using N = R_top + R_bottom - 1 with R_bottom(Rajive) = 2, N = R_top(Rajive) + 1. Statement 2 supplies two possible values for R_top(Rajive) (19 or 21), so substituting each gives two candidate class sizes: N = 20 and N = 22, not one.

Cross-check: test both candidates against every condition in the problem.

Candidate N

Raghu's rank

Rajive's rank

Rajive second-last?

Rajive adjacent to Raghu?

20

20 (last)

19

yes (20 - 1 = 19)

yes (|19-20| = 1)

22

20

21 (second-last)

yes (22 - 1 = 21)

yes (|21-20| = 1)

Both N = 20 and N = 22 satisfy every stated condition without contradiction. Since two different class sizes remain equally valid even after combining both statements, the class size is not uniquely determined.

Result: Even both statements put together are not sufficient to solve the problem.

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