If MUMBAI is coded as 202108, DELHI will be coded as ________ ?
2025
If MUMBAI is coded as 202108, DELHI will be coded as ________ ?
- A.
45289
- B.
34078
- C.
34178
- D.
34188
Attempted by 1 students.
Show answer & explanation
Correct answer: C
Concept: In this alphabet-to-number coding scheme, every letter of a word is replaced by a single digit: take the letter's position in the English alphabet (A = 1, B = 2, ..., Z = 26), subtract 1 from that position, and keep only the unit (last) digit of the result. Writing these digits in the same left-to-right order as the letters gives the code for the whole word.
Applying it to MUMBAI (checking the given code):
Letter | Position | Position − 1 | Unit digit |
|---|---|---|---|
M | 13 | 12 | 2 |
U | 21 | 20 | 0 |
M | 13 | 12 | 2 |
B | 2 | 1 | 1 |
A | 1 | 0 | 0 |
I | 9 | 8 | 8 |
Reading these digits in order — M, U, M, B, A, I — gives 2, 0, 2, 1, 0, 8, i.e. 202108, exactly the code given for MUMBAI. This confirms the rule.
Applying the same rule to DELHI:
Letter | Position | Position − 1 | Unit digit |
|---|---|---|---|
D | 4 | 3 | 3 |
E | 5 | 4 | 4 |
L | 12 | 11 | 1 |
H | 8 | 7 | 7 |
I | 9 | 8 | 8 |
Reading these digits in order — D, E, L, H, I — gives 3, 4, 1, 7, 8, so DELHI is coded as 34178.
Cross-check: Counting each letter's position from the other end of the alphabet (Z = 1st-from-the-end, Y = 2nd, ..., A = 26th) and converting back with position-from-A = 27 − position-from-Z independently gives D = 27−23 = 4, E = 27−22 = 5, L = 27−15 = 12, H = 27−19 = 8, I = 27−18 = 9 — the same positions used above, now re-derived by a separate counting method. Re-applying the rule to these confirms the code 34178.