Abhimanyu and supreet can together finish a work in 50 days. They worked…
2024
Abhimanyu and supreet can together finish a work in 50 days. They worked together for 35 days and then supreet left. After another 21 days, Abhimanyu finished the remaining work. In how many days Abhimanyu alone can finish the work?
- A.
35
- B.
54
- C.
52
- D.
70
Attempted by 29 students.
Show answer & explanation
Correct answer: D
Key idea: use work rates to find Abhimanyu's individual rate from the remaining work.
Combined rate of Abhimanyu and Supreet = 1/50 work per day.
Work done together in 35 days = 35 × (1/50) = 35/50 = 7/10 of the work.
Remaining work = 1 − 7/10 = 3/10.
Abhimanyu completes this remaining 3/10 in 21 days, so his daily rate = (3/10) ÷ 21 = 3/210 = 1/70.
Therefore, time for Abhimanyu alone to finish the whole work = reciprocal of his rate = 70 days.
Answer: 70 days.