X is a 5 digit number when we subtract the sum of the digits form X, it…

Key idea: a number minus the sum of its digits is always divisible by 9 (and therefore by 3).

• Write the number in digit form. If the digits are d0, d1, d2, ... then the number is d0 + 10·d1 + 100·d2 + ... .

• Observe that 10 ≡ 1 (mod 9), 100 ≡ 1 (mod 9), etc., so each place value is congruent to 1 modulo 9. Therefore the whole number is congruent to the sum of its digits modulo 9.

• Hence the difference (number − sum of digits) ≡ 0 (mod 9), so it is divisible by 9. Because any number divisible by 9 is also divisible by 3, the difference is divisible by 3 as well.

• This does not force divisibility by other numbers like 5, 6, or 12. For example, 10001 − (1+0+0+0+1) = 9999, which is divisible by 9 and 3 but not by 6 or 12.

Conclusion: The expression is always divisible by 9, and therefore by 3. The correct choice is the one listing 9 and 3.