Solve 10 * (480 – 80) + 144 / (3 + 3)2 = ?

Concept: A mixed-operations arithmetic expression must always be evaluated in one fixed order — Brackets, then Orders (exponents/roots), then Division and Multiplication (left to right), then Addition and Subtraction (left to right) — never by scanning the expression left to right operation-by-operation.

Application: Apply that order to this expression, one stage at a time.

1. Resolve the brackets first: 480 − 80 = 400, and 3 + 3 = 6.

2. Resolve the exponent next: 62 = 36.

3. Resolve division and multiplication, left to right: 144 ÷ 36 = 4, and 10 × 400 = 4000.

4. Resolve the addition last: 4000 + 4 = 4004.

Cross-check: The multiplication term (10 × 400 = 4000) and the division term (144 ÷ 62 = 4) are independent of each other — they are joined only by the final addition — so resolving them in either order and adding them together must give the same total.

Answer: 4000 + 4 = 4004.