Solve (600 + 650) – 400 ÷ 102 + 10

Concept: Under the BODMAS/PEMDAS order of operations, brackets are resolved first, then powers/roots (orders), then division and multiplication (left to right), and finally addition and subtraction (left to right). When two operations of equal precedence — such as addition and subtraction — appear next to each other, they must be evaluated strictly in the order they occur; they are never regrouped just because it looks convenient.

Applying this to the given expression:

1. Resolve the bracket: (600 + 650) = 1250, so the expression becomes 1250 – 400 ÷ 102 + 10.

2. Resolve the power (order): 102 = 100, giving 1250 – 400 ÷ 100 + 10.

3. Resolve the division: 400 ÷ 100 = 4, giving 1250 – 4 + 10.

4. Only addition and subtraction remain, at equal precedence, so evaluate strictly left to right: 1250 – 4 = 1246.

5. Then 1246 + 10 = 1256.

Cross-check: Rewriting the last step as signed-number addition, 1250 + (–4) + (+10) = 1250 + 6 = 1256 — the same result, confirming the value by an independent route.